\(\int x^2 \log ^3(c x) \, dx\) [16]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 10, antiderivative size = 45 \[ \int x^2 \log ^3(c x) \, dx=-\frac {2 x^3}{27}+\frac {2}{9} x^3 \log (c x)-\frac {1}{3} x^3 \log ^2(c x)+\frac {1}{3} x^3 \log ^3(c x) \]

[Out]

-2/27*x^3+2/9*x^3*ln(c*x)-1/3*x^3*ln(c*x)^2+1/3*x^3*ln(c*x)^3

Rubi [A] (verified)

Time = 0.02 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2342, 2341} \[ \int x^2 \log ^3(c x) \, dx=\frac {1}{3} x^3 \log ^3(c x)-\frac {1}{3} x^3 \log ^2(c x)+\frac {2}{9} x^3 \log (c x)-\frac {2 x^3}{27} \]

[In]

Int[x^2*Log[c*x]^3,x]

[Out]

(-2*x^3)/27 + (2*x^3*Log[c*x])/9 - (x^3*Log[c*x]^2)/3 + (x^3*Log[c*x]^3)/3

Rule 2341

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Log[c*x^
n])/(d*(m + 1))), x] - Simp[b*n*((d*x)^(m + 1)/(d*(m + 1)^2)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1
]

Rule 2342

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Lo
g[c*x^n])^p/(d*(m + 1))), x] - Dist[b*n*(p/(m + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{
a, b, c, d, m, n}, x] && NeQ[m, -1] && GtQ[p, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} x^3 \log ^3(c x)-\int x^2 \log ^2(c x) \, dx \\ & = -\frac {1}{3} x^3 \log ^2(c x)+\frac {1}{3} x^3 \log ^3(c x)+\frac {2}{3} \int x^2 \log (c x) \, dx \\ & = -\frac {2 x^3}{27}+\frac {2}{9} x^3 \log (c x)-\frac {1}{3} x^3 \log ^2(c x)+\frac {1}{3} x^3 \log ^3(c x) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00 \[ \int x^2 \log ^3(c x) \, dx=-\frac {2 x^3}{27}+\frac {2}{9} x^3 \log (c x)-\frac {1}{3} x^3 \log ^2(c x)+\frac {1}{3} x^3 \log ^3(c x) \]

[In]

Integrate[x^2*Log[c*x]^3,x]

[Out]

(-2*x^3)/27 + (2*x^3*Log[c*x])/9 - (x^3*Log[c*x]^2)/3 + (x^3*Log[c*x]^3)/3

Maple [A] (verified)

Time = 0.02 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.84

method result size
norman \(-\frac {2 x^{3}}{27}+\frac {2 x^{3} \ln \left (x c \right )}{9}-\frac {x^{3} \ln \left (x c \right )^{2}}{3}+\frac {x^{3} \ln \left (x c \right )^{3}}{3}\) \(38\)
risch \(-\frac {2 x^{3}}{27}+\frac {2 x^{3} \ln \left (x c \right )}{9}-\frac {x^{3} \ln \left (x c \right )^{2}}{3}+\frac {x^{3} \ln \left (x c \right )^{3}}{3}\) \(38\)
parallelrisch \(-\frac {2 x^{3}}{27}+\frac {2 x^{3} \ln \left (x c \right )}{9}-\frac {x^{3} \ln \left (x c \right )^{2}}{3}+\frac {x^{3} \ln \left (x c \right )^{3}}{3}\) \(38\)
parts \(\frac {x^{3} \ln \left (x c \right )^{3}}{3}-\frac {\frac {x^{3} c^{3} \ln \left (x c \right )^{2}}{3}-\frac {2 x^{3} c^{3} \ln \left (x c \right )}{9}+\frac {2 x^{3} c^{3}}{27}}{c^{3}}\) \(53\)
derivativedivides \(\frac {\frac {x^{3} c^{3} \ln \left (x c \right )^{3}}{3}-\frac {x^{3} c^{3} \ln \left (x c \right )^{2}}{3}+\frac {2 x^{3} c^{3} \ln \left (x c \right )}{9}-\frac {2 x^{3} c^{3}}{27}}{c^{3}}\) \(54\)
default \(\frac {\frac {x^{3} c^{3} \ln \left (x c \right )^{3}}{3}-\frac {x^{3} c^{3} \ln \left (x c \right )^{2}}{3}+\frac {2 x^{3} c^{3} \ln \left (x c \right )}{9}-\frac {2 x^{3} c^{3}}{27}}{c^{3}}\) \(54\)

[In]

int(x^2*ln(x*c)^3,x,method=_RETURNVERBOSE)

[Out]

-2/27*x^3+2/9*x^3*ln(x*c)-1/3*x^3*ln(x*c)^2+1/3*x^3*ln(x*c)^3

Fricas [A] (verification not implemented)

none

Time = 0.33 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.82 \[ \int x^2 \log ^3(c x) \, dx=\frac {1}{3} \, x^{3} \log \left (c x\right )^{3} - \frac {1}{3} \, x^{3} \log \left (c x\right )^{2} + \frac {2}{9} \, x^{3} \log \left (c x\right ) - \frac {2}{27} \, x^{3} \]

[In]

integrate(x^2*log(c*x)^3,x, algorithm="fricas")

[Out]

1/3*x^3*log(c*x)^3 - 1/3*x^3*log(c*x)^2 + 2/9*x^3*log(c*x) - 2/27*x^3

Sympy [A] (verification not implemented)

Time = 0.05 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.91 \[ \int x^2 \log ^3(c x) \, dx=\frac {x^{3} \log {\left (c x \right )}^{3}}{3} - \frac {x^{3} \log {\left (c x \right )}^{2}}{3} + \frac {2 x^{3} \log {\left (c x \right )}}{9} - \frac {2 x^{3}}{27} \]

[In]

integrate(x**2*ln(c*x)**3,x)

[Out]

x**3*log(c*x)**3/3 - x**3*log(c*x)**2/3 + 2*x**3*log(c*x)/9 - 2*x**3/27

Maxima [A] (verification not implemented)

none

Time = 0.19 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.64 \[ \int x^2 \log ^3(c x) \, dx=\frac {1}{27} \, {\left (9 \, \log \left (c x\right )^{3} - 9 \, \log \left (c x\right )^{2} + 6 \, \log \left (c x\right ) - 2\right )} x^{3} \]

[In]

integrate(x^2*log(c*x)^3,x, algorithm="maxima")

[Out]

1/27*(9*log(c*x)^3 - 9*log(c*x)^2 + 6*log(c*x) - 2)*x^3

Giac [A] (verification not implemented)

none

Time = 0.30 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.82 \[ \int x^2 \log ^3(c x) \, dx=\frac {1}{3} \, x^{3} \log \left (c x\right )^{3} - \frac {1}{3} \, x^{3} \log \left (c x\right )^{2} + \frac {2}{9} \, x^{3} \log \left (c x\right ) - \frac {2}{27} \, x^{3} \]

[In]

integrate(x^2*log(c*x)^3,x, algorithm="giac")

[Out]

1/3*x^3*log(c*x)^3 - 1/3*x^3*log(c*x)^2 + 2/9*x^3*log(c*x) - 2/27*x^3

Mupad [B] (verification not implemented)

Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.64 \[ \int x^2 \log ^3(c x) \, dx=\frac {x^3\,\left (9\,{\ln \left (c\,x\right )}^3-9\,{\ln \left (c\,x\right )}^2+6\,\ln \left (c\,x\right )-2\right )}{27} \]

[In]

int(x^2*log(c*x)^3,x)

[Out]

(x^3*(6*log(c*x) - 9*log(c*x)^2 + 9*log(c*x)^3 - 2))/27